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Oracle Regex for Path

Using Regex_replace you can extract bits of a path stored in an Oracle column using grouping backtracking.

select regexp_replace('/tsacrm1/inf/prdcrm1/JEE/CRMProduct/application/attachments/attachments/case/3709/Request to clear.txt.txt', '(.+)\/([^\/]+)\/([^\/]+)\/([^\/]+)\.([^\/]+)$','\3') from dual;

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